document.write( "Question 447019: Hi, I'm not sure which section to be asking these questions under, but i would really appreciate the help! :)\r
\n" ); document.write( "\n" ); document.write( "Find A and B such that: 2x/(2x-3)(x+5)=A/2x-3+B/x+5
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Algebra.Com's Answer #307791 by stanbon(75887)\"\" \"About 
You can put this solution on YOUR website!
Find A and B such that: 2x/(2x-3)(x+5)=A/(2x-3)+B/x+5
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\n" ); document.write( "lcd = (2x-3)(x+5)
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\n" ); document.write( "(2x+0)/lcd = [A(x+5)-B(2x-3)]/lcd
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\n" ); document.write( "Equate the numerators:
\n" ); document.write( "2x+0 = (A-2B)x+(5A+3B)
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\n" ); document.write( "Solve:
\n" ); document.write( "A-2B = 2
\n" ); document.write( "5A+3B=0
\n" ); document.write( "----
\n" ); document.write( "Multiply 1st by 5:
\n" ); document.write( "5A-10B = 10
\n" ); document.write( "5A+3B = 0
\n" ); document.write( "-------
\n" ); document.write( "Subtract and solve for \"B\":
\n" ); document.write( "13B = -10
\n" ); document.write( "B = -10/13
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\n" ); document.write( "Solve for \"A\":
\n" ); document.write( "A - 2B = 2
\n" ); document.write( "A -2(-10/13) = 2
\n" ); document.write( "A + 20/13 = 26/13
\n" ); document.write( "A = 6/13
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\n" ); document.write( "Cheers,
\n" ); document.write( "Stan H.
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