document.write( "Question 447019: Hi, I'm not sure which section to be asking these questions under, but i would really appreciate the help! :)\r
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document.write( "Find A and B such that: 2x/(2x-3)(x+5)=A/2x-3+B/x+5 \n" );
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Algebra.Com's Answer #307791 by stanbon(75887)![]() ![]() ![]() You can put this solution on YOUR website! Find A and B such that: 2x/(2x-3)(x+5)=A/(2x-3)+B/x+5 \n" ); document.write( "----- \n" ); document.write( "lcd = (2x-3)(x+5) \n" ); document.write( "------------------------- \n" ); document.write( "(2x+0)/lcd = [A(x+5)-B(2x-3)]/lcd \n" ); document.write( "---- \n" ); document.write( "Equate the numerators: \n" ); document.write( "2x+0 = (A-2B)x+(5A+3B) \n" ); document.write( "---- \n" ); document.write( "Solve: \n" ); document.write( "A-2B = 2 \n" ); document.write( "5A+3B=0 \n" ); document.write( "---- \n" ); document.write( "Multiply 1st by 5: \n" ); document.write( "5A-10B = 10 \n" ); document.write( "5A+3B = 0 \n" ); document.write( "------- \n" ); document.write( "Subtract and solve for \"B\": \n" ); document.write( "13B = -10 \n" ); document.write( "B = -10/13 \n" ); document.write( "---- \n" ); document.write( "Solve for \"A\": \n" ); document.write( "A - 2B = 2 \n" ); document.write( "A -2(-10/13) = 2 \n" ); document.write( "A + 20/13 = 26/13 \n" ); document.write( "A = 6/13 \n" ); document.write( "------------------------------- \n" ); document.write( "Cheers, \n" ); document.write( "Stan H. \n" ); document.write( "=============== \n" ); document.write( " |