document.write( "Question 445726: What are three consecutive odd integers so that five times the middle integer is nine more than twice the sum of the first and third integers? \n" ); document.write( "
Algebra.Com's Answer #307762 by rwm(914)\"\" \"About 
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x
\n" ); document.write( "x+2
\n" ); document.write( "x+4
\n" ); document.write( "5*(x+2)=9+2*(x+x+4)\r
\n" ); document.write( "\n" ); document.write( "5x+10=9+2*(2x+4)
\n" ); document.write( "5x+1=4x+8
\n" ); document.write( "x=7
\n" ); document.write( "7, 9 and 11
\n" ); document.write( "check\r
\n" ); document.write( "\n" ); document.write( "5*(9)=9+2*(7+11)
\n" ); document.write( "45=9+2*18
\n" ); document.write( "45=9+36
\n" ); document.write( "45=45
\n" ); document.write( "ok
\n" ); document.write( "
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