document.write( "Question 445726: What are three consecutive odd integers so that five times the middle integer is nine more than twice the sum of the first and third integers? \n" ); document.write( "
Algebra.Com's Answer #307762 by rwm(914)![]() ![]() ![]() You can put this solution on YOUR website! x \n" ); document.write( "x+2 \n" ); document.write( "x+4 \n" ); document.write( "5*(x+2)=9+2*(x+x+4)\r \n" ); document.write( "\n" ); document.write( "5x+10=9+2*(2x+4) \n" ); document.write( "5x+1=4x+8 \n" ); document.write( "x=7 \n" ); document.write( "7, 9 and 11 \n" ); document.write( "check\r \n" ); document.write( "\n" ); document.write( "5*(9)=9+2*(7+11) \n" ); document.write( "45=9+2*18 \n" ); document.write( "45=9+36 \n" ); document.write( "45=45 \n" ); document.write( "ok \n" ); document.write( " |