document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=46398>Question 46398</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Sally brought three chocolate bars and a pack of gum and paid $1.75. Jake brought two chocolate bars and four packs of gum and paid $2.00. Find the cost of a chocolate bar and the cost of a pack of gum?\r<BR>\n" );
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document.write( "Thank you. I have gotten so far as x = chocolate bar and y = gum. </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #30773 by </B><A HREF=/tutors/aboutme.mpl?userid=saltzy57><B>saltzy57(8)</B></A><img src=\"/images/stars/stars-05.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=saltzy57><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=30773\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> 3x + 1y =1.75<BR>\n" );
document.write( "2x + 4y =2.00\r<BR>\n" );
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document.write( "To find the cost of the choclate bar we must eliminate the gum from our equation.\r<BR>\n" );
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document.write( "One way to do that is to Multiply the first equation by 4 and substract the two equations\r<BR>\n" );
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document.write( "4(3x+Y)= 1.75<BR>\n" );
document.write( " 12x +4y = 7.00 now substract the 2nd equation from first<BR>\n" );
document.write( "- 2x +4y = 2.00 you get the following equation\r<BR>\n" );
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document.write( "10x= 5.00 solve for x by dividing both sides by 10<BR>\n" );
document.write( "x=.50\r<BR>\n" );
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document.write( "solve for y by plugging in value for x in either equation.\r<BR>\n" );
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document.write( "2*(.5) + 4*y = 2.00<BR>\n" );
document.write( "1.00+4y=2.00<BR>\n" );
document.write( "4y=1.00<BR>\n" );
document.write( "y=.25 </SPAN>\n" );
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