document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=46398>Question 46398</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Sally brought three chocolate bars and a pack of gum and paid $1.75. Jake brought two chocolate bars and four packs of gum and paid $2.00. Find the cost of a chocolate bar and the cost of a pack of gum?\r<BR>\n" );
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document.write( "Thank you. I have gotten so far as x = chocolate bar and y = gum. </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #30771 by </B><A HREF=/tutors/aboutme.mpl?userid=tutorcecilia><B>tutorcecilia(2152)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=tutorcecilia><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=tutorcecilia><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=30771\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> This is a systems of equations because there are two linear conditions:<BR>\n" );
document.write( "3candy + 1 gum = $1.75 [First condition]<BR>\n" );
document.write( "2candy + 4 gum = $2.00 [Second condition]<BR>\n" );
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document.write( "3C + 1G = 1.75 [Solve using any type of method elimination, substituion, etc.]<BR>\n" );
document.write( "2C + 4G = 2.00 \r<BR>\n" );
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document.write( "3C + 1G = 1.75 [Try the elimination method]<BR>\n" );
document.write( "2C + 4G = 2.00 <BR>\n" );
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document.write( "-2(3C + 1G = 1.75) [Multiply through with -2 to eliminate the \"C\" term <BR>\n" );
document.write( "+3(2C + 4G = 2.00) [Multiply through with 3 to eliminate the \"C\" term]<BR>\n" );
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document.write( "-6C -2G = -3.50 [Multiply through with -2 to eliminate the \"C\" term]<BR>\n" );
document.write( "+6C +12G = 6.00 [Multiply through with 3 to eliminate the \"C\" term]<BR>\n" );
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document.write( "-6C -2G = -3.50  [Perform the indicated operations]<BR>\n" );
document.write( "+6C +12G = 6.00 <BR>\n" );
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document.write( "0C +10G = 2.50<BR>\n" );
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document.write( "10G = 2.50  [Solve for \"G\"]<BR>\n" );
document.write( "G = 2.50/10<BR>\n" );
document.write( "Gum = .25 cents each \r<BR>\n" );
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document.write( "2C + 4(.25) = 2.00 [Plug-in G=.227 into either original equation]<BR>\n" );
document.write( "2C + 1.00 = 2.00 [Solve for \"C\"]<BR>\n" );
document.write( "2C + 1.00 - 1.00 = 2.00 - 1.00 [Simplify]<BR>\n" );
document.write( "2C = 1.00<BR>\n" );
document.write( "2C/2=1.00/2<BR>\n" );
document.write( "Candy=0.50 cents each\r<BR>\n" );
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document.write( "3C + 1G = 1.75 [Plug-in C=0.50 and G=.25 into the orginal equations]<BR>\n" );
document.write( "3(0.50)+1(.25)=1.75[Plug-in C=0.50 and G=.25 into the orginal equations]<BR>\n" );
document.write( "1.75=1.75 [Checks out]<BR>\n" );
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document.write( "2C + 4G = 2.00 [Plug-in C=0.50 and G=.25 into the orginal equations]<BR>\n" );
document.write( "2(0.50) + 4(.25) = 2.00 <BR>\n" );
document.write( "1.00 + 1.00=2.00<BR>\n" );
document.write( "2.00=2.00 [checks out]\r<BR>\n" );
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document.write( "_______________ </SPAN>\n" );
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