document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=446815>Question 446815</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Hi! My question is: What are the dimensions of a rectangle having perimeter 28 cm and a diagonal of length 10 cm. I'm hoping that using the pythagorean theorem is the correct way to go about this, but I keep getting strange answers. Any help would be greatly appreciated! Thanks! </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #307686 by </B><A HREF=/tutors/aboutme.mpl?userid=richard1234><B>richard1234(7193)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=richard1234><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=richard1234><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=307686\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Using the Pythagorean theorem works well. If you can intuit the problem, recognize the 6-8-10 right triangle and note that 2(6+8) = 28, that works even better.\r<BR>\n" );
document.write( "<BR>\n" );
document.write( "\n" );
document.write( "If you were to use the Pythagorean theorem, then you could say that\r<BR>\n" );
document.write( "<BR>\n" );
document.write( "\n" );
document.write( "<IMG STYLE=\"max-width:80%;\" SRC=\"/cgi-bin/rendertex.cgi?\LARGE \sqrt{x^2 + y^2} = 10 \Rightarrow x^2 + y^2 = 100\"> given the constraint that x+y = 14. Then, you could say that y = 14-x, replace to obtain the equation\r<BR>\n" );
document.write( "<BR>\n" );
document.write( "\n" );
document.write( "<IMG STYLE=\"max-width:80%;\" SRC=\"/cgi-bin/rendertex.cgi?\LARGE x^2 + (14-x)^2 = 100\">\r<BR>\n" );
document.write( "<BR>\n" );
document.write( "\n" );
document.write( "Then solve for x and y. </SPAN>\n" );
document.write( "</TD></TR></TABLE>\n" );