document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=446591>Question 446591</A>: <I><SPAN STYLE=\"word-break: break-all;\"> identify the following series as arithmetic , geometric , or neither.\r<BR>\n" );
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document.write( "1.  3a + 3a^2 + 3a^3 + 3a^4 +...+ 3a^n +...\r<BR>\n" );
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document.write( "2.  -3+3-3+3-3+3....\r<BR>\n" );
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document.write( "3.  n=1 (3+na) >> above this is a sideways 8 and a sideways M <<< </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #307681 by </B><A HREF=/tutors/aboutme.mpl?userid=richard1234><B>richard1234(7193)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=richard1234><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=richard1234><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=307681\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> 1. Geometric, common ratio is a.\r<BR>\n" );
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document.write( "2. Geometric, common ratio is -1. This series does not converge though, the ratio has to be strictly between -1 and 1 for the series to converge.\r<BR>\n" );
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document.write( "3. I presume you mean\r<BR>\n" );
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document.write( "<IMG STYLE=\"max-width:80%;\" SRC=\"/cgi-bin/rendertex.cgi?\LARGE \sum_{n=1}^{\infty} (3 + na)\"> where <IMG STYLE=\"max-width:80%;\" SRC=\"/cgi-bin/rendertex.cgi?\infty\"> is the infinity symbol and <IMG STYLE=\"max-width:80%;\" SRC=\"/cgi-bin/rendertex.cgi?\sum\"> is the Greek uppercase letter sigma. If a is a constant, then the series is\r<BR>\n" );
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document.write( "<IMG STYLE=\"max-width:80%;\" SRC=\"/cgi-bin/rendertex.cgi?\LARGE (3 + n) + (3 + 2n) + (3 + 3n) + ...\">, in which the sequence determined is arithmetic with common difference n. </SPAN>\n" );
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