document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=46387>Question 46387</A>: <I><SPAN STYLE=\"word-break: break-all;\">  Factor completely.     x2 – 3x – 18<BR>\n" );
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document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #30766 by </B><A HREF=/tutors/aboutme.mpl?userid=corrie21><B>corrie21(4)</B></A><img src=\"/images/stars/iconNewId_16x16.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=corrie21><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=30766\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Since x^2 will be the first to factor you make two sets of parathesis and put x as the first factor in each<BR>\n" );
document.write( "(x   )(x   )<BR>\n" );
document.write( "Next you have to figure out which numbers that make -18 will also come out to a -3 when you add or subtract.<BR>\n" );
document.write( "For example, the factors of 18 are 1, 2, 3, 6, 9, 18.  Which of those numbers could make a negative 3?  A negative 6 and a positive 3 will make a -3 when you add them, and it will make a -18 when you multiply them.  So heres how you finish the problem...<BR>\n" );
document.write( "(x-6)(x+3)<BR>\n" );
document.write( "To check your answer, FOIL it out. </SPAN>\n" );
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