document.write( "Question 446733: Ben has to go to soccer practice. He and his brother leave their house and drive to the school averaging 50 miles per hour. On the way home they averaged only 30 miles per hour due to traffic. What was the average speed of the trip? The answer is NOT 40 miles per hour. \n" ); document.write( "
Algebra.Com's Answer #307652 by ankor@dixie-net.com(22740)\"\" \"About 
You can put this solution on YOUR website!
He and his brother leave their house and drive to the school averaging 50 miles per hour.
\n" ); document.write( " On the way home they averaged only 30 miles per hour due to traffic.
\n" ); document.write( " What was the average speed of the trip?
\n" ); document.write( ":
\n" ); document.write( "Let a = average speed for the round trip
\n" ); document.write( ":
\n" ); document.write( "Let d = one-way distance to school
\n" ); document.write( ";
\n" ); document.write( "Write time equation: time = dist/speed
\n" ); document.write( ":
\n" ); document.write( "To time + return time = total time
\n" ); document.write( "\"d%2F50\" + \"d%2F30\" = \"%282d%29%2Fa\"
\n" ); document.write( "Multiply by 150a to clear the denominators
\n" ); document.write( "150a*\"d%2F50\" + 150a*\"d%2F30\" = 150a*\"%282d%29%2Fa\"
\n" ); document.write( "cancel the denominators
\n" ); document.write( "3a(d) + 5a(d) = 150(2d)
\n" ); document.write( "Divide thru by d, we don't need that
\n" ); document.write( "3a + 5a = 150(2)
\n" ); document.write( "8a = 300
\n" ); document.write( "a = \"300%2F8\"
\n" ); document.write( "a = 37.5 mph is the average speed for the round trip
\n" ); document.write( ":
\n" ); document.write( ":
\n" ); document.write( "You can confirm this. Use a one-way dist of 150 mi
\n" ); document.write( "150/50 + 150/30 = 300/37.5
\n" ); document.write( "
\n" );