document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=446742>Question 446742</A>: <I><SPAN STYLE=\"word-break: break-all;\"> The supplementary of an angle measures 25 degrees more than it's compliment.find the measure of the angle </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #307641 by </B><A HREF=/tutors/aboutme.mpl?userid=Alan3354><B>Alan3354(69443)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=Alan3354><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=Alan3354><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=307641\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> The supplementary of an angle measures 25 degrees more than it's compliment.find the measure of the angle<BR>\n" );
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document.write( "It's the supplement of an angle, not the supplementary.<BR>\n" );
document.write( "It's complement, not compliment.<BR>\n" );
document.write( "it's = it is.<BR>\n" );
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document.write( "a = the angle<BR>\n" );
document.write( "180 - a = the supplement<BR>\n" );
document.write( "90 - a = the complement<BR>\n" );
document.write( "180 - a = 90 - a + 25<BR>\n" );
document.write( "180 = 115<BR>\n" );
document.write( "No solution.<BR>\n" );
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document.write( "The supplement of an angle is always 90 deg more than the complement.<BR>\n" );
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