document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=431443>Question 431443</A>: <I><SPAN STYLE=\"word-break: break-all;\"> how much water should be mixed with 6 gallons of 30% alcohol to get a 20% alcohol solution </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #307635 by </B><A HREF=/tutors/aboutme.mpl?userid=jorel1380><B>jorel1380(3719)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=jorel1380><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=jorel1380><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=307635\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> 6 gallons of 30% alcohol=1.8 gallons of pur alcohol--<BR>\n" );
document.write( ".20*x gallons=1.8<BR>\n" );
document.write( "x=1.8/.2=9 gallons<BR>\n" );
document.write( "Since you already have 6 gallons, you need 3 gallons of pure water to thin the mix down to 20%.. </SPAN>\n" );
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