document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=446736>Question 446736</A>: <I><SPAN STYLE=\"word-break: break-all;\"> a(T)=-2t(squared)+32T+12<BR>\n" );
document.write( "the amount of nitrogen dioxide A was present in the air. T is the number of hours after 6 am. Use this function to find the time at which the nitrogen dioxide level was at its maximum. Graph the parabola. </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #307634 by </B><A HREF=/tutors/aboutme.mpl?userid=stanbon><B>stanbon(75887)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=stanbon><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=307634\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> a(T)=-2t(squared)+32T+12<BR>\n" );
document.write( "the amount of nitrogen dioxide A was present in the air. T is the number of hours after 6 am. Use this function to find the time at which the nitrogen dioxide level was at its maximum. Graph the parabola.<BR>\n" );
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document.write( "a(T) = -2T^2+32T+12<BR>\n" );
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document.write( "Quadratic with a = -2 ; b = 32<BR>\n" );
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document.write( "Max occurs when T = -b/(2a) = -32/(2*-2) = 8 hrs<BR>\n" );
document.write( "---<BR>\n" );
document.write( "Time at max nitrogen dioxide level 6am + 8 hr = 2pm<BR>\n" );
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document.write( "Cheers,<BR>\n" );
document.write( "Stan H. </SPAN>\n" );
document.write( "</TD></TR></TABLE>\n" );