document.write( "Question 432177: Chemist has 20% and 50% solution of acid available. how many liters of each solution should be mixed to obtain 10 liters of 40% acid solution? \n" ); document.write( "
Algebra.Com's Answer #307622 by jorel1380(3719) You can put this solution on YOUR website! x+y=10 \n" ); document.write( ".2x+.5y=4 \n" ); document.write( "2x+5y=40 \n" ); document.write( "2x+2y=20 \n" ); document.write( "3y=20 \n" ); document.write( "y=20/3 \n" ); document.write( "x=10/3 \n" ); document.write( "You need 10/3 ltrs. of 20% solution, and 20/3 ltrs. of 50% solution.. \n" ); document.write( " |