document.write( "Question 446685: 3x
\n" ); document.write( "-
\n" ); document.write( "y\r
\n" ); document.write( "\n" ); document.write( "x=3/5 and y= 2 1/2
\n" ); document.write( "
\n" ); document.write( "

Algebra.Com's Answer #307603 by stanbon(75887)\"\" \"About 
You can put this solution on YOUR website!
(3x)/y\r
\n" ); document.write( "\n" ); document.write( "x=3/5 and y= 2 1/2
\n" ); document.write( "----------------------------\r
\n" ); document.write( "\n" ); document.write( "(3*(3/5))/(5/2)
\n" ); document.write( "-----
\n" ); document.write( "= (9/5)/(5/2)
\n" ); document.write( "---
\n" ); document.write( "= (9/5)*(2/5)
\n" ); document.write( "------
\n" ); document.write( "= 18/25
\n" ); document.write( "==============
\n" ); document.write( "Cheers,
\n" ); document.write( "Stan H.
\n" ); document.write( "==============
\n" ); document.write( "
\n" );