Algebra.Com's Answer #307594 by MathLover1(20850)  You can put this solution on YOUR website!  \n" );
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document.write( " Solved by pluggable solver: Solving a System of Linear Equations by Elimination/Addition | \n" );
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document.write( " Lets start with the given system of linear equations \n" );
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document.write( " In order to solve for one variable, we must eliminate the other variable. So if we wanted to solve for y, we would have to eliminate x (or vice versa). \n" );
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document.write( " So lets eliminate x. In order to do that, we need to have both x coefficients that are equal but have opposite signs (for instance 2 and -2 are equal but have opposite signs). This way they will add to zero. \n" );
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document.write( " So to make the x coefficients equal but opposite, we need to multiply both x coefficients by some number to get them to an equal number. So if we wanted to get -9 and 3 to some equal number, we could try to get them to the LCM. \n" );
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document.write( " Since the LCM of -9 and 3 is -9, we need to multiply both sides of the top equation by 1 and multiply both sides of the bottom equation by 3 like this: \n" );
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document.write( " Multiply the top equation (both sides) by 1 \n" );
document.write( " Multiply the bottom equation (both sides) by 3 \n" );
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document.write( " So after multiplying we get this: \n" );
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document.write( " Notice how -9 and 9 and 22 and 3 add to zero (ie ) \n" );
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document.write( " However 22 and -18 add to 4 (ie ); \n" );
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document.write( " So we're left with \n" );
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document.write( " which means no value of x or y value will satisfy the system of equations. So there are no solutions \n" );
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document.write( " So this system is inconsistent | \n" );
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document.write( "check with a graph:\r \n" );
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document.write( "as you can see from the graph, lines are parallel; so, system doesn't have a solution. \n" );
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