document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=446609>Question 446609</A>: <I><SPAN STYLE=\"word-break: break-all;\"> The sum of a number and its reciprocal is given below.  <BR>\n" );
document.write( "29/10.   Find the numbers.<BR>\n" );
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document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #307560 by </B><A HREF=/tutors/aboutme.mpl?userid=sudhanshu_kmr><B>sudhanshu_kmr(1152)</B></A><img src=\"/images/stars/stars-12.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=sudhanshu_kmr><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=sudhanshu_kmr><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=307560\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> <BR>\n" );
document.write( "x + 1/x = 29/10\r<BR>\n" );
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document.write( "=> 10x^2 + 10 = 29x\r<BR>\n" );
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document.write( "=>  10x^2 -29x +10 =0\r<BR>\n" );
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document.write( "=> 10x^2 -25x -4x +10 =0\r<BR>\n" );
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document.write( "=> 5x(2x -5) -2(2x-5) = 0\r<BR>\n" );
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document.write( "=> (5x -2)(2x-5) = 0\r<BR>\n" );
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document.write( "numbers are 2/5  and  5/2.\r<BR>\n" );
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