document.write( "Question 446499: How much of an alloy that is 40% copper should be mixed with 100 ounces of an alloy that is 60% copper in order to get an alloy that is 50% copper? \n" ); document.write( "

Algebra.Com's Answer #307533 by ewatrrr(24785) $\"\"$ $\"About$

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document.write( "Hi,
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document.write( "Let x represent how much of an alloy that is 40% copper that is needed:
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document.write( " .40x + .60*100 = .50(100+x)
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document.write( "     .10*100 = .10x
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document.write( "      .10*100/.10 = x
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document.write( "           100 = x\r
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document.write( "CHECKING our Answer***
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document.write( " .40*100 + .60*100 = 40 + 60 = 100 = .50*200 \n" );
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