document.write( "Question 446486: Two town A and B are 300 km apart. C is exacly halfway between A and B. A cyclist departs from B to C at x km/h at 9h00 and one hour later a second cyclist depatrs form A to C, 5 km/h faster than the first cyclist. They reach C simultaneously.\r
\n" ); document.write( "\n" ); document.write( "1.1) Calculate, in terms of x, the time each cyclist requires to reach C.
\n" ); document.write( "1.2) Calculate at what time they will reach C.
\n" ); document.write( "

Algebra.Com's Answer #307508 by ankor@dixie-net.com(22740)\"\" \"About 
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Two town A and B are 300 km apart. C is exacly halfway between A and B.
\n" ); document.write( " A cyclist departs from B to C at x km/h at 9h00 and one hour later a second
\n" ); document.write( " cyclist departs form A to C, 5 km/h faster than the first cyclist.
\n" ); document.write( " They reach C simultaneously.
\n" ); document.write( ":
\n" ); document.write( "1.1) Calculate, in terms of x, the time each cyclist requires to reach C.
\n" ); document.write( "Time = dist/speed
\n" ); document.write( "A cyclist: t(x) = \"150%2Fx\" hrs
\n" ); document.write( "B cyclist: t(x) = \"150%2F%28%28x%2B5%29%29\" hrs
\n" ); document.write( ":
\n" ); document.write( "Find x
\n" ); document.write( "B's time + 1 hr = A's time
\n" ); document.write( "\"150%2F%28%28x%2B5%29%29\" + 1 = \"150%2Fx\"
\n" ); document.write( ":
\n" ); document.write( "Multiply by x(x+5), results:
\n" ); document.write( "150x + x(x+5) = 150(x+5)
\n" ); document.write( "150x + x^2 + 5x = 150x + 750
\n" ); document.write( "x^2 + 5x + 150x - 150x - 750 = 0
\n" ); document.write( "x^2 + 5x - 750 = 0
\n" ); document.write( ":
\n" ); document.write( "Factors to
\n" ); document.write( "(x+30)(x-25) = 0
\n" ); document.write( ":
\n" ); document.write( "the positive solution
\n" ); document.write( "x = 25 km/h is A's speed
\n" ); document.write( "then
\n" ); document.write( "25 + 5 = 30 km/h is B's speed
\n" ); document.write( ":
\n" ); document.write( "find the travel times
\n" ); document.write( "A: 150/25 = 6 hrs
\n" ); document.write( "B: 150/30 = 5 hrs
\n" ); document.write( ":
\n" ); document.write( ":
\n" ); document.write( "1.2) Calculate at what time they will reach C.
\n" ); document.write( "9:00 + 6 = 3 PM; A will reach C
\n" ); document.write( "and
\n" ); document.write( "10:00 + 5 = 3 PM; B will reach C also
\n" ); document.write( "
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