document.write( "Question 446476: A farmer buys cattle and sheep for an amount of $53800. He buys 100 animals in total. The sheep were $250 each and the cattle were $730 each.How many sheep and how many cattle did he buy in total? \n" ); document.write( "
Algebra.Com's Answer #307484 by Leaf W.(135)![]() ![]() You can put this solution on YOUR website! x = number of cattle the farmer buys \n" ); document.write( "100 - x = number of sheep the farmer buys (because if he buys 100 animals in total, and x of them are cattle, the remainder--100 - x-- is the number of sheep he buys) \n" ); document.write( "$250*(the number of sheep) + $730*(the number of cattle) = $53800 \n" ); document.write( "250(100 - x) + 730x = 53800 \n" ); document.write( "Distribute: 25000 - 250x + 730x = 53800 \n" ); document.write( "Combine like terms: 25000 + 480x = 53800 \n" ); document.write( "Subtract 25000 from both sides: 480x = 28800 \n" ); document.write( "Divide both sides by 480: x = 60 \n" ); document.write( "THEREFORE, THE FARMER BOUGHT 60 CATTLE. \n" ); document.write( "To find the number of sheep, plug 60 in for the value of x in the expression for the number of sheep (100 - x) \n" ); document.write( "100 - 60 = 40 \n" ); document.write( "THEREFORE, THE FARMER BOUGHT 40 SHEEP. \n" ); document.write( "==> THE FARMER BOUGHT 40 SHEEP AND 60 CATTLE. \n" ); document.write( " |