document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=446482>Question 446482</A>: <I><SPAN STYLE=\"word-break: break-all;\"> If 5 added to a number and the sum is tripled, the result is 19 more than number.  Find the number. </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #307481 by </B><A HREF=/tutors/aboutme.mpl?userid=Leaf+W.><B>Leaf W.(135)</B></A><img src=\"/images/stars/stars-09.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=Leaf+W.><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=Leaf+W.><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=307481\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> x = number<BR>\n" );
document.write( "If 5 is added to a number = x + 5<BR>\n" );
document.write( "And the sum is tripled = 3(x + 5)<BR>\n" );
document.write( "19 more than the number = x + 19<BR>\n" );
document.write( "3(x + 5) = x + 19<BR>\n" );
document.write( "Distribute the 3 into the x and 5: 3x + 15 = x + 19<BR>\n" );
document.write( "Subtract 15 from both sides: 3x = x + 4<BR>\n" );
document.write( "Subtract x from both sides: 2x = 4<BR>\n" );
document.write( "Divide both sides by 2: x = 2<BR>\n" );
document.write( "***<BR>\n" );
document.write( "Therefore, the number is 2. </SPAN>\n" );
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