document.write( "Question 446440: When three pumps, A, B, C, are running together, they can pump 3200 gal per hour. When only A and B are running, 1800 gal per hour can be pumped, when only A and C are running 2000 gal_per hour can be pumped. What is the pumping capacity of each pump?
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\n" ); document.write( "\n" ); document.write( " $6300 is invested, part of it at !0% and part of it at 6%. For a certain year, the total yield is $502.00 How much was invested at each rate?
\n" ); document.write( "How much was invested at 10%
\n" ); document.write( "How much was invested at 6%
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Algebra.Com's Answer #307466 by mananth(16946)\"\" \"About 
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A= xgal/h, B=ygal/h, C= zgal/h\r
\n" ); document.write( "\n" ); document.write( "x+y+z=3200....1
\n" ); document.write( "x+y=1800......2
\n" ); document.write( "x+z= 2000......3\r
\n" ); document.write( "\n" ); document.write( "multiply (2) by -1 and add to (1)
\n" ); document.write( "-x-y=-1800
\n" ); document.write( "add it to (1)
\n" ); document.write( "z=1400
\n" ); document.write( "In eq(3)
\n" ); document.write( "x+z=2000
\n" ); document.write( "plug z
\n" ); document.write( "x+1400=2000
\n" ); document.write( "x=600
\n" ); document.write( "...
\n" ); document.write( "Plug x & z in (1)
\n" ); document.write( "600+y+1400=3200
\n" ); document.write( "y=1200
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\n" ); document.write( "Part I 10.00% per annum
\n" ); document.write( "Part II 6.00% per annum
\n" ); document.write( "x+y=6300 ------------------------1
\n" ); document.write( "10.00%x+ 6.00%y=$502.00
\n" ); document.write( "Multiply by 100
\n" ); document.write( "10x+6y=$50,200.00 --------2
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\n" ); document.write( "Multiply (1) by -10
\n" ); document.write( "we get
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\n" ); document.write( "-10x-10y=-63000.00
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\n" ); document.write( "Add this to (2)
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\n" ); document.write( "-4y=-$12,800.00
\n" ); document.write( "divide by -4
\n" ); document.write( "y=$3,200.00 investment at 6.00%
\n" ); document.write( "Balance $3,100.00 investment at 10.00%\r
\n" ); document.write( "\n" ); document.write( "m.ananth@hotmail.ca\r
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