document.write( "Question 46352: The period of a simple pendulum is directly proportional to the square root of its length. If a pendulum has a length of 6 feet and a period of 2 seconds, to what length should it be shortened to achieve a 1 second period? \n" ); document.write( "

Algebra.Com's Answer #30745 by Nate(3500) $\"\"$ $\"About$

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p = period
\n" ); document.write( "l = length
\n" ); document.write( " $\"p%2Fsqrt%28l%29+=+p%2Fsqrt%28l%29\"$
\n" ); document.write( " $\"2%2Fsqrt%286%29+=+1%2Fsqrt%28l%29\"$
\n" ); document.write( " $\"sqrt%28l%29%2A2+=+sqrt%286%29\"$
\n" ); document.write( " $\"l+=+%28sqrt%286%29%2F2%29%5E2\"$
\n" ); document.write( " $\"l+=+6%2F4+=+1.5\"$
\n" ); document.write( "6 - 1.5 = 4.5 feet it should be shortened \n" ); document.write( "

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