document.write( "Question 446391: Determine in each the gradient and equation of the line joining the two points
\n" ); document.write( "Determine the co-ordinates for the X- intercept and Y - intercept for each of the lines
\n" ); document.write( "(-3,4) and (9, 12)
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Algebra.Com's Answer #307440 by lwsshak3(11628)\"\" \"About 
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Determine in each the gradient and equation of the line joining the two points
\n" ); document.write( "Determine the co-ordinates for the X- intercept and Y - intercept for each of the lines
\n" ); document.write( "(-3,4) and (9, 12)
\n" ); document.write( "..
\n" ); document.write( "Using point-slope formula to find slope or gradient as you call it.
\n" ); document.write( "y1-y2=m(x1-x2)
\n" ); document.write( "m=(y1-y2)/(x1-x2)=change in y/change in x
\n" ); document.write( "m=(12-4)/(9-(-3))=8/12=2/3
\n" ); document.write( "Standard form for equation of line: y=mx+b, m=slope, b= y-intercept
\n" ); document.write( "To find b, plug in x and y from either of given points like (9,12) into the standard form, then solve for b
\n" ); document.write( "12=(2/3)*9+b
\n" ); document.write( "b=12-6=3
\n" ); document.write( "Equation:
\n" ); document.write( "y=(2/3)x+3
\n" ); document.write( "y-intercept=3
\n" ); document.write( "To find x-intercept, set y=0, then solve for x
\n" ); document.write( "0=(2/3)x+3
\n" ); document.write( "(2/3)x=-3
\n" ); document.write( "2x=-9
\n" ); document.write( "x=-9/2
\n" ); document.write( "ans:
\n" ); document.write( "Equation of line: y=(2/3)x+3
\n" ); document.write( "y-intercept=3
\n" ); document.write( "x-intercept=-9/2\r
\n" ); document.write( "\n" ); document.write( "See graph of line below:\r
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\n" ); document.write( "\n" ); document.write( "\"+graph%28+300%2C+300%2C+-10%2C+10%2C+-10%2C+10%2C+%282%2F3%29x%2B3%29+\"
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