document.write( "Question 446394: Would I add 4 to both sides to solve this? The first step would be 5 *2 = 6 and so on, right? How to solve?\r
\n" ); document.write( "\n" ); document.write( "5(2x+3)≥4(6x-1)\r
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Algebra.Com's Answer #307426 by stanbon(75887)\"\" \"About 
You can put this solution on YOUR website!
How to solve?
\n" ); document.write( "5(2x+3)≥4(6x-1) \r
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\n" ); document.write( "10x+15 >= 24x-4
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\n" ); document.write( "Subtract 10x from both sides.
\n" ); document.write( "Add 4 to both sides.
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\n" ); document.write( "19 >= 12x
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\n" ); document.write( "Divide both sides by 12.
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\n" ); document.write( "19/12 >= x
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\n" ); document.write( "Write from left to right:
\n" ); document.write( "x <= 19/12
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\n" ); document.write( "Cheers,
\n" ); document.write( "Stan H.
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