document.write( "Question 446385: A researcher knows that the population mean among college students taking the Social Conformity Test is a \"neutral\" 100. (scores higher than 100 are assumed to represent more conformity than average, and those lower than 100 indicate less conformity). A random sample of 30 students was selected, and the following values were recorded:
\n" ); document.write( "sample mean = 103
\n" ); document.write( "sample standard deviation= 10.83
\n" ); document.write( "Is this sample significantly different than the population?
\n" ); document.write( "State the null and alternative hypotheses.
\n" ); document.write( "

Algebra.Com's Answer #307414 by stanbon(75887)\"\" \"About 
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A researcher knows that the population mean among college students taking the Social Conformity Test is a \"neutral\" 100. (scores higher than 100 are assumed to represent more conformity than average, and those lower than 100 indicate less conformity).
\n" ); document.write( " A random sample of 30 students was selected, and the following values were recorded:
\n" ); document.write( "sample mean = 103
\n" ); document.write( "sample standard deviation= 10.83
\n" ); document.write( "Is this sample significantly different than the population?
\n" ); document.write( "State the null and alternative hypotheses.
\n" ); document.write( "----
\n" ); document.write( "Ho: u = 100
\n" ); document.write( "Ha: u is not equal to 100 (the sample is significantly different)
\n" ); document.write( "---------
\n" ); document.write( "t(103) = (103-100)/[10.83/sqrt(30)] = 1.5172..
\n" ); document.write( "---
\n" ); document.write( "p-value = 2P(t>1.5172 when df = 29) == 2*0.07 = 14%
\n" ); document.write( "----
\n" ); document.write( "Since the p-value is greater than 5%, fail to reject
\n" ); document.write( "Ho at the 5% level of significance.
\n" ); document.write( "The sample is not significantly different than the population.
\n" ); document.write( "===========================
\n" ); document.write( "Cheers,
\n" ); document.write( "Stan H.
\n" ); document.write( "
\n" );