document.write( "Question 5891: A motorboat can travel at a rate of 15 mph in still water. It went downstream on a river in 4 hours. It took 6 hours to return the same distance. What is the rate of the current. How far did the boat go?\r
\n" ); document.write( "\n" ); document.write( "My answer was: Rate of current -30
\n" ); document.write( "The boat went 150 miles
\n" ); document.write( " Is this right? Thanks!
\n" ); document.write( "

Algebra.Com's Answer #3074 by Abbey(339)\"\" \"About 
You can put this solution on YOUR website!
let x = the current
\n" ); document.write( "rate with the current = 15+x
\n" ); document.write( "rate against the current = 15-x
\n" ); document.write( "distance both ways is equal
\n" ); document.write( "rate * time = distance
\n" ); document.write( "distance going=(15+x)4
\n" ); document.write( "distance coming = (15-x)6
\n" ); document.write( "set these equations equal to one another because distance both ways is equal:
\n" ); document.write( "(15+x)4=(15-x)6
\n" ); document.write( "60+4x=90-6x
\n" ); document.write( "subtract 60 from both sides
\n" ); document.write( "4x=30-6x
\n" ); document.write( "add 6x to both sides
\n" ); document.write( "10x=30
\n" ); document.write( "divide both sides by 10
\n" ); document.write( "x=3\r
\n" ); document.write( "\n" ); document.write( "the current = 3mph
\n" ); document.write( "(15+3)4= distance
\n" ); document.write( "18*4 = distance
\n" ); document.write( "72 miles = distance\r
\n" ); document.write( "\n" ); document.write( "verify:
\n" ); document.write( "(15-3)*6 = distance
\n" ); document.write( "12*6 = distance
\n" ); document.write( "72 miles = distance\r
\n" ); document.write( "\n" ); document.write( "The boat traveled 144 miles total in a 3 mph current
\n" ); document.write( "
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