document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=46343>Question 46343</A>This question is from textbook <A HREF=http://www.amazon.com/exec/obidos/ASIN/0072549017/algebrahomeworkh>beginning algebra</A><BR>\n" );
document.write( ": <I><SPAN STYLE=\"word-break: break-all;\">  6. The length of a rectangle is 1 cm longer than its width. If the diagonal<BR>\n" );
document.write( "    of the rectangle is 4 cm, what are the dimensions (the length and width) of<BR>\n" );
document.write( "    rectangle?\r<BR>\n" );
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document.write( "   Is this right so far. I don't understand after this.\r<BR>\n" );
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document.write( "   x2 +(x+1)2=4sq<BR>\n" );
document.write( "   x2 +x2 + 1x +1 = 16<BR>\n" );
document.write( "   2x2 + 1x -   = 0      I don't understand how to get the next part? </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #30735 by </B><A HREF=/tutors/aboutme.mpl?userid=checkley71><B>checkley71(8403)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=checkley71><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=30735\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> you have the right idea but made a few Yistakes\r<BR>\n" );
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document.write( "x~2+(x+1)~2=4~2 or x~2+x~2+2x+1=16 or 2x~2+2x+1-16=0 or 2x~2+2x-15=0 or<BR>\n" );
document.write( "x~2+x-7.5 now using the quadradic equation -- the solutions are x=2.283882181415 & x=-3.283882181415. Thus the solution is the width of the rectangle is 2.28cm & the length is 2.28+1 or 3.28cm.\r<BR>\n" );
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document.write( "Proof 2.283882181415*2.283882181415+3.2823882181415*3.283888211415=4*4 or 5.21612+10.78388=16 or 16=16    </SPAN>\n" );
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