document.write( "Question 446306: Trains A and B are traveling in the same direction on parallel tracks. Train A is traveling at 40 miles per hour and Train B is traveling at 50 miles per hour. Train A passes a station at 11:25AM. If Train B passes the same station at 11:37AM, at what time will Train B catch up to Train A?\r
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document.write( "When will Train B catch up with Train A? \n" );
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Algebra.Com's Answer #307344 by ankor@dixie-net.com(22740)![]() ![]() You can put this solution on YOUR website! Trains A and B are traveling in the same direction on parallel tracks. \n" ); document.write( " Train A is traveling at 40 miles per hour and Train B is traveling at 50 miles per hour. \n" ); document.write( " Train A passes a station at 11:25AM. \n" ); document.write( "If Train B passes the same station at 11:37AM, at what time will Train B catch up to Train A? \n" ); document.write( "When will Train B catch up with Train A? \n" ); document.write( ": \n" ); document.write( "From the given information, we know that Train B is 12 min behind A at at 11:25 am \n" ); document.write( "therefore Train B is: \n" ); document.write( " \n" ); document.write( ": \n" ); document.write( "Let t = time required for Train B to catch Train A \n" ); document.write( ": \n" ); document.write( "Write a distance equation; dist = speed * time \n" ); document.write( ": \n" ); document.write( "Train B dist = Train A dist + 10 mi \n" ); document.write( "50t = 40t + 10 \n" ); document.write( "50t - 40t = 10 \n" ); document.write( "10t = 10 \n" ); document.write( "t = 1 hr for B to catch A \n" ); document.write( ": \n" ); document.write( "Find the time from 11:25 am: \n" ); document.write( "11:25 + 1:00 = 12:25 pm, Train B catches Train A \n" ); document.write( ": \n" ); document.write( ": \n" ); document.write( "Check this by finding the actual distance each train travels \n" ); document.write( "B travels: 50*1 = 50 mi \n" ); document.write( "while A travels: 40*1 = 40 mi \n" ); document.write( " |