document.write( "Question 446306: Trains A and B are traveling in the same direction on parallel tracks. Train A is traveling at 40 miles per hour and Train B is traveling at 50 miles per hour. Train A passes a station at 11:25AM. If Train B passes the same station at 11:37AM, at what time will Train B catch up to Train A?\r
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Algebra.Com's Answer #307344 by ankor@dixie-net.com(22740)\"\" \"About 
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Trains A and B are traveling in the same direction on parallel tracks.
\n" ); document.write( " Train A is traveling at 40 miles per hour and Train B is traveling at 50 miles per hour.
\n" ); document.write( " Train A passes a station at 11:25AM.
\n" ); document.write( "If Train B passes the same station at 11:37AM, at what time will Train B catch up to Train A?
\n" ); document.write( "When will Train B catch up with Train A?
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\n" ); document.write( "From the given information, we know that Train B is 12 min behind A at at 11:25 am
\n" ); document.write( "therefore Train B is:
\n" ); document.write( "\"12%2F60\" * 50 = 10 miles behind Train A at that time.
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\n" ); document.write( "Let t = time required for Train B to catch Train A
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\n" ); document.write( "Write a distance equation; dist = speed * time
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\n" ); document.write( "Train B dist = Train A dist + 10 mi
\n" ); document.write( "50t = 40t + 10
\n" ); document.write( "50t - 40t = 10
\n" ); document.write( "10t = 10
\n" ); document.write( "t = 1 hr for B to catch A
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\n" ); document.write( "Find the time from 11:25 am:
\n" ); document.write( "11:25 + 1:00 = 12:25 pm, Train B catches Train A
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\n" ); document.write( "Check this by finding the actual distance each train travels
\n" ); document.write( "B travels: 50*1 = 50 mi
\n" ); document.write( "while A travels: 40*1 = 40 mi
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