document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=446283>Question 446283</A>: <I><SPAN STYLE=\"word-break: break-all;\"> The hypotenuse of a right triangle is 4 cm longer than the shortest side and 2 cm longer than the remaining side.  Find the dimensions of the triangle.<BR>\n" );
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document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #307323 by </B><A HREF=/tutors/aboutme.mpl?userid=stanbon><B>stanbon(75887)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=stanbon><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=307323\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> The hypotenuse of a right triangle is 4 cm longer than the shortest side and 2 cm longer than the remaining side. Find the dimensions of the triangle.\r<BR>\n" );
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document.write( "Let shortest side be \"x\".<BR>\n" );
document.write( "The hypotenuse = \"x+4\"<BR>\n" );
document.write( "And 3rd side is \"x-2\".<BR>\n" );
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document.write( "Equation:<BR>\n" );
document.write( "x^2 + (x-2)^2 = (x+4)^2<BR>\n" );
document.write( "x^2 + x^2-4x+4 = x^2+4x+16<BR>\n" );
document.write( "x^2-8x-12 = 0<BR>\n" );
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document.write( "(x-6)(x-2) = 0<BR>\n" );
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document.write( "x = 6 or x = 2<BR>\n" );
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document.write( "Cheers,<BR>\n" );
document.write( "Stan H.<BR>\n" );
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