document.write( "Question 446269: A committee consists of 9 men and 14 women. In how many ways can a subcommittee of 3 men and 7 women be chosen? \n" ); document.write( "
Algebra.Com's Answer #307322 by jorel1380(3719)![]() ![]() You can put this solution on YOUR website! 9C3x14C7= \n" ); document.write( "(9x8x7x6!/3x2x6!)x(14x13x12x11x10x9x8x7!/7x6x5x4x3x2x7!)= \n" ); document.write( "(3x4x7)x(2x13x11x2x3x2)=288288 different committees possible.. \n" ); document.write( " |