document.write( "Question 446237: In the equation of a parabola y = (x-5)^2 + 4, I understand the vertex is (5,4). I don't understand why we take the opposite of what is in the parenthesis with the x. It seems to me we would translate the vertex of the graph left 5 units, not right 5 units. Can someone please help me understand this? Thanks.
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Algebra.Com's Answer #307303 by stanbon(75887)\"\" \"About 
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In the equation of a parabola y = (x-5)^2 + 4, I understand the vertex is (5,4). I don't understand why we take the opposite of what is in the parenthesis with the x. It seems to me we would translate the vertex of the graph left 5 units, not right 5 units.
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\n" ); document.write( "Try thinking of it this way.
\n" ); document.write( "If you had the equation y = x^2+4
\n" ); document.write( "y would be 4 when x is zero.
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\n" ); document.write( "You have the equation y = (x-5)^2 + 4
\n" ); document.write( "y will be 4 when (x-5) is zero.
\n" ); document.write( "That happens when x = 5.
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\n" ); document.write( "What happened before at x = 0 now
\n" ); document.write( "happens when x = 5.
\n" ); document.write( "The graph has moved 5 to the right.
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\n" ); document.write( "This is the way I teach the idea.
\n" ); document.write( "Think of the x-axis as a time line where
\n" ); document.write( "time flows from left to right i.e. 0 seconds, 1 second, ...., 5 seconds etc.
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\n" ); document.write( "t is some time on the t-axis.
\n" ); document.write( "t-5 is 5 seconds later on the t-axis.
\n" ); document.write( "\"later\" means to the right.
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\n" ); document.write( "t+5 would mean 5 seconds earlier.
\n" ); document.write( "\"earlier\" means to the left.\r
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\n" ); document.write( "Hope this helps.
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\n" ); document.write( "Cheers,
\n" ); document.write( "Stan H.
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