document.write( "Question 446181: The perimeter of rectangularposter is included 80in. The length is 10 in. greater than the width. Find the length. \n" ); document.write( "
Algebra.Com's Answer #307266 by Leaf W.(135)![]() ![]() You can put this solution on YOUR website! 1. Name variables-- \n" ); document.write( "width: x \n" ); document.write( "length: \"the length is 10 in. greater than the width\": width + 10: x + 10 \n" ); document.write( "2. Perimeter of a rectangle: 2(length) + 2(width) \n" ); document.write( "Plug in variables named in Step 1: 2(x + 10) + 2(x) \n" ); document.write( "In the problem, it states that the perimeter is 80 in., so put that equal to 80: 2(x + 10) + 2x = 80 \n" ); document.write( "3. Simplify and solve for x. \n" ); document.write( "Distribute: 2x + 20 + 2x = 80 \n" ); document.write( "Combine like terms: 4x + 20 = 60 \n" ); document.write( "Subtract 20 from both sides: 4x = 60 \n" ); document.write( "Divide both sides by 4: x = 15 \n" ); document.write( "Therefore, x (the width) is 15. However, the problem is looking for the length. To find the length, plug this value for x (15) into the expression for length (x + 10) found in Step 1. \n" ); document.write( "15 + 10 \n" ); document.write( "25 \n" ); document.write( "Therefore, the length of the rectangular poster is 25 inches. \n" ); document.write( " |