document.write( "Question 446181: The perimeter of rectangularposter is included 80in. The length is 10 in. greater than the width. Find the length. \n" ); document.write( "
Algebra.Com's Answer #307266 by Leaf W.(135)\"\" \"About 
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1. Name variables--
\n" ); document.write( "width: x
\n" ); document.write( "length: \"the length is 10 in. greater than the width\": width + 10: x + 10
\n" ); document.write( "2. Perimeter of a rectangle: 2(length) + 2(width)
\n" ); document.write( "Plug in variables named in Step 1: 2(x + 10) + 2(x)
\n" ); document.write( "In the problem, it states that the perimeter is 80 in., so put that equal to 80: 2(x + 10) + 2x = 80
\n" ); document.write( "3. Simplify and solve for x.
\n" ); document.write( "Distribute: 2x + 20 + 2x = 80
\n" ); document.write( "Combine like terms: 4x + 20 = 60
\n" ); document.write( "Subtract 20 from both sides: 4x = 60
\n" ); document.write( "Divide both sides by 4: x = 15
\n" ); document.write( "Therefore, x (the width) is 15. However, the problem is looking for the length. To find the length, plug this value for x (15) into the expression for length (x + 10) found in Step 1.
\n" ); document.write( "15 + 10
\n" ); document.write( "25
\n" ); document.write( "Therefore, the length of the rectangular poster is 25 inches.
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