document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=446191>Question 446191</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Can someone help me with this problem?\r<BR>\n" );
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document.write( "Please help with this problem\r<BR>\n" );
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document.write( "6300 is invested, part of it at 10% and part of it at 8%. For a cerain year, the total is 566. How much was invest at each rate </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #307253 by </B><A HREF=/tutors/aboutme.mpl?userid=robertb><B>robertb(5830)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=robertb><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=robertb><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=307253\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> The equation is \r<BR>\n" );
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document.write( "0.10x + 0.08*(6300 - x) = 566.\r<BR>\n" );
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document.write( "Just solve for x (that would be the portion invested at 10%). </SPAN>\n" );
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