document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=445304>Question 445304</A>: <I><SPAN STYLE=\"word-break: break-all;\"> if alpha and beta are the measures of two first quadrant angles and tan alpha = 4/5 and tan beta = 3/4, find tan(alpha+beta) </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #307241 by </B><A HREF=/tutors/aboutme.mpl?userid=lwsshak3><B>lwsshak3(11628)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=lwsshak3><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=307241\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> if alpha and beta are the measures of two first quadrant angles and tan alpha = 4/5 and tan beta = 3/4, find tan(alpha+beta)<BR>\n" );
document.write( "..<BR>\n" );
document.write( "let a=alpha<BR>\n" );
document.write( "let b=beta\r<BR>\n" );
document.write( "\n" );
document.write( "tan (a+b)=(tan a+tan b)/(1-tan a tan b)<BR>\n" );
document.write( "              =(4/5+3/4)/(1-4/5*3/4)<BR>\n" );
document.write( "              =(16/20+15/20)/1-12/20<BR>\n" );
document.write( "              =(31/20)/(8/20)<BR>\n" );
document.write( "tan (a+b)=31/8 (ans) </SPAN>\n" );
document.write( "</TD></TR></TABLE>\n" );