document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=446085>Question 446085</A>: <I><SPAN STYLE=\"word-break: break-all;\"> how many gallons 65%antifreeze and how many 20% antifreeze should be mixed up to obtain 50 gallons of 56% mixture of antifreeze? </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #307185 by </B><A HREF=/tutors/aboutme.mpl?userid=mananth><B>mananth(16946)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=mananth><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=mananth><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=307185\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> 	percent	----------------			quantity							<BR>\n" );
document.write( "Antifreeze I	65----------------x	gallons					<BR>\n" );
document.write( "Antifreeze II	20	----------------50-x gallons					<BR>\n" );
document.write( "Total	56.00%	----------------50 gallons									<BR>\n" );
document.write( "												<BR>\n" );
document.write( "65x+20(50-x)=56	*50<BR>\n" );
document.write( "65x+1000-20x=2800		<BR>\n" );
document.write( "65x-20x=2800-1000		<BR>\n" );
document.write( "45x=1800							<BR>\n" );
document.write( "/45										<BR>\n" );
document.write( "x=40 gallons 65.00%		<BR>\n" );
document.write( "10 gallons 20.00%		<BR>\n" );
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