document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=446104>Question 446104</A>: <I><SPAN STYLE=\"word-break: break-all;\"> A ladder is resting against a wall.  The top of the ladder touches the wall at a height of 9ft. Find the length of the ladder if the length is 3ft more than its distance from the wall. </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #307183 by </B><A HREF=/tutors/aboutme.mpl?userid=mananth><B>mananth(16946)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=mananth><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=mananth><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=307183\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> wall ladder distance =x<BR>\n" );
document.write( "length of ladder = x+3<BR>\n" );
document.write( "height touching the wall = 9\r<BR>\n" );
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document.write( "(x+3)^2=x^2+9^2<BR>\n" );
document.write( "x^2+6x+9=x^2+81<BR>\n" );
document.write( "6x=81-9<BR>\n" );
document.write( "6x=72<BR>\n" );
document.write( "/6<BR>\n" );
document.write( "x=12 feet<BR>\n" );
document.write( "ladder ===>x+3= 12+3=15 feet<BR>\n" );
document.write( "m.ananth@hotmail.ca </SPAN>\n" );
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