document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=446009>Question 446009</A>: <I><SPAN STYLE=\"word-break: break-all;\"> A landscaper has an empty 1,000-gallon fish pond to fill. His hose<BR>\n" );
document.write( "delivers one quart of water every thirty seconds. He turns on the<BR>\n" );
document.write( "hose at 7:00 A.M. and leaves. When he returns at the same time the<BR>\n" );
document.write( "next day, the pond is:<BR>\n" );
document.write( "A. approximately one half full.<BR>\n" );
document.write( "B. about three quarters full.<BR>\n" );
document.write( "C. almost full.<BR>\n" );
document.write( "D. overflowing.<BR>\n" );
document.write( " <BR>\n" );
document.write( "How do I solve this problem? </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #307162 by </B><A HREF=/tutors/aboutme.mpl?userid=ankor@dixie-net.com><B>ankor@dixie-net.com(22740)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=ankor@dixie-net.com><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=ankor@dixie-net.com><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=307162\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> A landscaper has an empty 1,000-gallon fish pond to fill.<BR>\n" );
document.write( " His hose delivers one quart of water every thirty seconds.<BR>\n" );
document.write( " He turns on the hose at 7:00 A.M. and leaves.<BR>\n" );
document.write( " When he returns at the same time the next day, the pond is:<BR>\n" );
document.write( ":<BR>\n" );
document.write( "that would be 1/2 gal/min<BR>\n" );
document.write( ":<BR>\n" );
document.write( "24 hrs * 60 min * half gallon<BR>\n" );
document.write( "<IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=%2824+%2A+60+%2A+.5%29%2F1000 ALIGN=MIDDLE  ALT=\"%2824+%2A+60+%2A+.5%29%2F1000\"   DISABLED_style= \"max-width:90%; height:auto;\" > = <IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=720%2F1000 ALIGN=MIDDLE  ALT=\"720%2F1000\"   DISABLED_style= \"max-width:90%; height:auto;\" >, about three-quarters full </SPAN>\n" );
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