document.write( "Question 445932: x^2-18x-y^2+12y=19, find the center and vertices \n" ); document.write( "
Algebra.Com's Answer #307075 by ewatrrr(24785)\"\" \"About 
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\n" ); document.write( "Hi, Note:
\n" ); document.write( "Standard Form of an Equation of an Hyperbola opening right and left is
\n" ); document.write( " \"%28x-h%29%5E2%2Fa%5E2+-+%28y-k%29%5E2%2Fb%5E2+=+1\"
\n" ); document.write( "where Pt(h,k) is a center with vertices 'a' units right and left of center.
\n" ); document.write( " x^2-18x-y^2+12y=19
\n" ); document.write( "(x-9)^2 -81 -[(y-6)^2-36] = 19
\n" ); document.write( "(x-9)^2 -81 -(y-6)^2+36 = 19
\n" ); document.write( "(x-9)^2 -(y-6)^2 = 64
\n" ); document.write( "\"%28x-9%29%5E2%2F64+-%28y-6%29%5E2%2F64=1\" C(9,6) with vertices V(1,6) and V(17,6)
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