document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=445924>Question 445924</A>: <I><SPAN STYLE=\"word-break: break-all;\"> The equation of a circle is (x - 3)2 + (y + 2)2 = 25. The point (8, -2) is on the circle.\r<BR>\n" );
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document.write( "What is the equation of the line that is tangent to the circle at (8, -2)?\r<BR>\n" );
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document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #307072 by </B><A HREF=/tutors/aboutme.mpl?userid=Gogonati><B>Gogonati(855)</B></A><img src=\"/images/stars/stars-11.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=Gogonati><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=Gogonati><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=307072\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> First we find the slope of the line which passes through the (8, -2) and <BR>\n" );
document.write( "center of the circle (3,-2). This line contains the radius and is perpendicular to the tangent line at (8, -2).\r<BR>\n" );
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document.write( "The slope is:<IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=m=%28-2%2B2%29%2F%288-3%29=0 ALIGN=MIDDLE  ALT=\"m=%28-2%2B2%29%2F%288-3%29=0\"   DISABLED_style= \"max-width:90%; height:auto;\" >, since its slope is zero the line is parallel \r<BR>\n" );
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document.write( "to the x-axis, and its equation is: y=-2. The equation of the tangent line at\r<BR>\n" );
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document.write( " (8, -2) will be: x=8.\r<BR>\n" );
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document.write( "Answer:The equation of the line is x=8.\r<BR>\n" );
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