document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=445863>Question 445863</A>: <I><SPAN STYLE=\"word-break: break-all;\"> If a merchant has two types of tea, one work $2.70 per kilogram and the other worth $3.00 per kilogram, how many kilograms of each type should the merchant use in order to produce 30 kilograms of a blend that is worth $2.95 per kilogram?  </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #307053 by </B><A HREF=/tutors/aboutme.mpl?userid=mananth><B>mananth(16946)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=mananth><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=mananth><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=307053\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> 	Price	----------------quantity							<BR>\n" );
document.write( "Tea Type I 2.7----------------x	pounds					<BR>\n" );
document.write( "Tea Type II 3----------------30-x pounds					<BR>\n" );
document.write( "Total	2.95----------------30						<BR>\n" );
document.write( "2.7x+3(30-x)=2.95*30<BR>\n" );
document.write( "2.7x+90	-3x=88.5		<BR>\n" );
document.write( "2.7x-3x=88.5-90		<BR>\n" );
document.write( "-0.3x=-1.5							<BR>\n" );
document.write( "/-0.3										<BR>\n" );
document.write( "x=5	pounds$	2.70		<BR>\n" );
document.write( "25 pounds $3.00		<BR>\n" );
document.write( " </SPAN>\n" );
document.write( "</TD></TR></TABLE>\n" );