document.write( "Question 445889: If there were 600 people at a play, the total receipts were 9,800 pesos, and the admission price was 20 pesos for adults and 10 pesos for children, how many adults and how many children were in attendance? .....thank you \n" ); document.write( "
Algebra.Com's Answer #307047 by mananth(16946)\"\" \"About 
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Adult x Numbers
\n" ); document.write( "Child ------------ y Numbers
\n" ); document.write( "x+y=600 .............1
\n" ); document.write( "20x+10y=9800 .............2
\n" ); document.write( "Eliminate y
\n" ); document.write( "multiply (1)by -10
\n" ); document.write( "Multiply (2) by 1
\n" ); document.write( "-10x-10y=-6000
\n" ); document.write( "20x+10y=9800
\n" ); document.write( "Add the two equations
\n" ); document.write( "10x= 3800
\n" ); document.write( "/10
\n" ); document.write( "x=380
\n" ); document.write( "plug value of x in (1)
\n" ); document.write( "x+y=600
\n" ); document.write( "380+y=600
\n" ); document.write( "y=600 -380
\n" ); document.write( "y=220
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