document.write( "Question 445023: Solve the following problem using \"Complete the Square\" Method\r
\n" );
document.write( "\n" );
document.write( "2x^2+14x-1=0 \n" );
document.write( "
Algebra.Com's Answer #307044 by lwsshak3(11628)![]() ![]() ![]() You can put this solution on YOUR website! Solve the following problem using \"Complete the Square\" Method \n" ); document.write( "2x^2+14x-1=0 \n" ); document.write( ".. \n" ); document.write( "2x^2+14x-1=0 \n" ); document.write( "move constant to right side \n" ); document.write( "2x^2+14x=1 \n" ); document.write( "factor out 2 on left side so x^2 has a coefficient of 1. To complete the square, take 1/2 the coefficient of x then square it (7/2)^2=49/4 \n" ); document.write( "2(x^2+7x+49/4)=1+49/2 (since I added 2*49/4 to complete the square, I must also add it to the right side.) \n" ); document.write( "2(x^2+7x+49/4)=(2/2)+(49/2)=51/2 \n" ); document.write( "divide both sides by 2 \n" ); document.write( "(x+7/2)^2=51/4 \n" ); document.write( "take sqrt of both sides \n" ); document.write( "x+7/2=+-sqrt(51/4)=+-√51/2 \n" ); document.write( "x=-7/2+-√51/2 \n" ); document.write( "x=(-7-√51)/2=-7.07 \n" ); document.write( "or \n" ); document.write( "x=(-7+√51/2=.0707 \n" ); document.write( " |