document.write( "Question 445023: Solve the following problem using \"Complete the Square\" Method\r
\n" ); document.write( "\n" ); document.write( "2x^2+14x-1=0
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Algebra.Com's Answer #307044 by lwsshak3(11628)\"\" \"About 
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Solve the following problem using \"Complete the Square\" Method
\n" ); document.write( "2x^2+14x-1=0
\n" ); document.write( "..
\n" ); document.write( "2x^2+14x-1=0
\n" ); document.write( "move constant to right side
\n" ); document.write( "2x^2+14x=1
\n" ); document.write( "factor out 2 on left side so x^2 has a coefficient of 1. To complete the square, take 1/2 the coefficient of x then square it (7/2)^2=49/4
\n" ); document.write( "2(x^2+7x+49/4)=1+49/2 (since I added 2*49/4 to complete the square, I must also add it to the right side.)
\n" ); document.write( "2(x^2+7x+49/4)=(2/2)+(49/2)=51/2
\n" ); document.write( "divide both sides by 2
\n" ); document.write( "(x+7/2)^2=51/4
\n" ); document.write( "take sqrt of both sides
\n" ); document.write( "x+7/2=+-sqrt(51/4)=+-√51/2
\n" ); document.write( "x=-7/2+-√51/2
\n" ); document.write( "x=(-7-√51)/2=-7.07
\n" ); document.write( "or
\n" ); document.write( "x=(-7+√51/2=.0707
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