document.write( "Question 445879: solve this a perimeter of a rectangle is 252ft. the length exceeds width by 50 inches. find the length and width \n" ); document.write( "
Algebra.Com's Answer #307032 by edjones(8007)\"\" \"About 
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2(L+w)=P
\n" ); document.write( "L=w+50
\n" ); document.write( "2(w+50+w)=3024 Substitute w+50 for L. 252'=3024\"
\n" ); document.write( "2(2w+50)=3024
\n" ); document.write( "4w+100=3024
\n" ); document.write( "4w=2924
\n" ); document.write( "w=731\"
\n" ); document.write( "L=781\"
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