document.write( "Question 445879: solve this a perimeter of a rectangle is 252ft. the length exceeds width by 50 inches. find the length and width \n" ); document.write( "
Algebra.Com's Answer #307032 by edjones(8007)![]() ![]() You can put this solution on YOUR website! 2(L+w)=P \n" ); document.write( "L=w+50 \n" ); document.write( "2(w+50+w)=3024 Substitute w+50 for L. 252'=3024\" \n" ); document.write( "2(2w+50)=3024 \n" ); document.write( "4w+100=3024 \n" ); document.write( "4w=2924 \n" ); document.write( "w=731\" \n" ); document.write( "L=781\" \n" ); document.write( ". \n" ); document.write( "Ed \n" ); document.write( " |