document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=445611>Question 445611</A>: <I><SPAN STYLE=\"word-break: break-all;\"> the cooling system in ann's car contains 19 liters of 30% antifreeze. how much coolant must be drained out and replaced with 80% antifreeze so that the system will contain 50% antifreeze. how much of the original coolant will be left in the car? </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #307026 by </B><A HREF=/tutors/aboutme.mpl?userid=jorel1380><B>jorel1380(3719)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=jorel1380><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=jorel1380><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=307026\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> x+y=19<BR>\n" );
document.write( ".30x+.80y=.5(x+y)<BR>\n" );
document.write( ".30x+.80y=.5x+.5y<BR>\n" );
document.write( ".3y=.2x<BR>\n" );
document.write( "3y=2x<BR>\n" );
document.write( "2x+2y=38<BR>\n" );
document.write( "3y+2y=38<BR>\n" );
document.write( "5y=38<BR>\n" );
document.write( "y=38/5<BR>\n" );
document.write( "x=57/5<BR>\n" );
document.write( "38/5 liters of coolant must be drained and replaced with 80% antifreeze to get the desired mix.  57/5 liters of 30% coolant can be left in the radiator.. </SPAN>\n" );
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