document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=445784>Question 445784</A>: <I><SPAN STYLE=\"word-break: break-all;\"> i have to use substitution to solve this linear system <BR>\n" );
document.write( "x + 4y = 17<BR>\n" );
document.write( "5x + 2y = -5 </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #306983 by </B><A HREF=/tutors/aboutme.mpl?userid=rfer><B>rfer(16322)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=rfer><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=306983\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> x=-4y+17<BR>\n" );
document.write( "-------------<BR>\n" );
document.write( "5(-4y+17)+2y=-5<BR>\n" );
document.write( "-20y+85+2y=-5<BR>\n" );
document.write( "-18y=-90<BR>\n" );
document.write( "y=5<BR>\n" );
document.write( "---------------<BR>\n" );
document.write( "5x+2*5=-5<BR>\n" );
document.write( "5x=-15<BR>\n" );
document.write( "x=-3<BR>\n" );
document.write( "----------------<BR>\n" );
document.write( "-3+4*5=17<BR>\n" );
document.write( "-3+20=17 </SPAN>\n" );
document.write( "</TD></TR></TABLE>\n" );