document.write( "Question 445357: ln(x+2) + lnx =ln 35 \n" ); document.write( "

Algebra.Com's Answer #306977 by lwsshak3(11628) $\"\"$ $\"About$

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ln(x+2) + lnx =ln 35
\n" ); document.write( "..
\n" ); document.write( "ln(x+2) + lnx =ln 35
\n" ); document.write( "ln(x+2) + lnx -ln 35=0
\n" ); document.write( "ln(x(x+2)/35=0
\n" ); document.write( "convert to exponential form: (base raised to log of number=number)
\n" ); document.write( "e^0=(x(x+2)/35=1
\n" ); document.write( "(x^2+2x)=35
\n" ); document.write( "x^2+2x-35=0
\n" ); document.write( "(x+7)(x-5)=0
\n" ); document.write( "x=-7 (reject, x>0)
\n" ); document.write( "x=5 (ans) \n" ); document.write( "

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