document.write( "Question 445631: Find 3 consecutive odd integers whose sum is 43 (Hint: if n represents the smallest of the three integers, n+2 and n+4, represent the other two numbers) \n" ); document.write( "
Algebra.Com's Answer #306958 by Alan3354(69443)![]() ![]() You can put this solution on YOUR website! The sum of 3 consecutive integers, in order, odd, or even, is divisible by 3. \n" ); document.write( "43 is not, so there's no solution \n" ); document.write( "----------- \n" ); document.write( "If we pretend we don't know that: \n" ); document.write( "n + n+2 + n+4 = 43 \n" ); document.write( "3n+6 = 43 \n" ); document.write( "3n = 37 \n" ); document.write( "n = 37/3, not an integer \n" ); document.write( "---------- \n" ); document.write( "Examples: \n" ); document.write( "9+11+13 = 33 \n" ); document.write( "23+25+27 = 75 \n" ); document.write( "---------- \n" ); document.write( "20+22+24 = 66 \n" ); document.write( "7+8+9 = 24 \n" ); document.write( "All the sums are divisible by 3 \n" ); document.write( " \n" ); document.write( " |