document.write( "Question 445532: The length of a rectangle is 5 more than its width. If perimeter is 58ft, what are length and width? \n" ); document.write( "
Algebra.Com's Answer #306895 by stanbon(75887)![]() ![]() ![]() You can put this solution on YOUR website! The length of a rectangle is 5 more than its width. \n" ); document.write( "If perimeter is 58ft, what are length and width? \n" ); document.write( "------------------- \n" ); document.write( "Let width be \"W\". \n" ); document.write( "Then length = \"W+5\". \n" ); document.write( "------- \n" ); document.write( "Perimeter = 2(width + length) \n" ); document.write( "58 = 2(W + W+5) \n" ); document.write( "29 = 2W+5 \n" ); document.write( "2W = 24 \n" ); document.write( "W = 12 ft (width) \n" ); document.write( "--- \n" ); document.write( "length = W+5 = 17 ft \n" ); document.write( "======================== \n" ); document.write( "Cheers, \n" ); document.write( "Stan H. \n" ); document.write( " \n" ); document.write( " |