document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=445463>Question 445463</A>: <I><SPAN STYLE=\"word-break: break-all;\"> one leg of a right triangle is 7 units longer than the length of the other leg if the hypotenuse is 13 then find the other two legs  decide what to make x write and equation  would it be 13=7+2(x) with x=3? <BR>\n" );
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document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #306836 by </B><A HREF=/tutors/aboutme.mpl?userid=rajagopalan><B>rajagopalan(174)</B></A><img src=\"/images/stars/stars-09.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=rajagopalan><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=rajagopalan><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=306836\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Let one leg = x<BR>\n" );
document.write( "other leg=x+7<BR>\n" );
document.write( "then x^2+(x+7)^2=13^2<BR>\n" );
document.write( "x^2+x^2+14x+49=169<BR>\n" );
document.write( "2x^2+14x+49=169<BR>\n" );
document.write( "2x^2+14x+49-169=0<BR>\n" );
document.write( "2x^2+14x-120=0<BR>\n" );
document.write( "x^2+7x-60=0 divide both sides by 2<BR>\n" );
document.write( "x^2+12x-5x-60=0<BR>\n" );
document.write( "x(x+12)-5(x+12)=0<BR>\n" );
document.write( "(x-5)(x+12)=0<BR>\n" );
document.write( "giving x=5 or -12. ignore negative value<BR>\n" );
document.write( "we get x=5<BR>\n" );
document.write( "other side=5+7=12<BR>\n" );
document.write( "okay<BR>\n" );
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