document.write( "Question 46234: solve 9^(2x + 1) = 27^x \n" ); document.write( "
Algebra.Com's Answer #30683 by longjonsilver(2297)![]() ![]() You can put this solution on YOUR website! these types of questions look really hard but at very simple (usually :-) ).\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "The thing to spot is that the 2 base numbers, here 9 and 27 are both powers of 3. We will convert the numbers to 3 and then we will have \"3 to the power of whatever\" equals \"3 to the power of something else\". So, the 2 powers must be the same thing.\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "So now we can say that \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "CHECK: \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "so we are correct.\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "jon \n" ); document.write( " \n" ); document.write( " |