document.write( "Question 46234: solve 9^(2x + 1) = 27^x \n" ); document.write( "
Algebra.Com's Answer #30683 by longjonsilver(2297)\"\" \"About 
You can put this solution on YOUR website!
these types of questions look really hard but at very simple (usually :-) ).\r
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\n" ); document.write( "\n" ); document.write( "The thing to spot is that the 2 base numbers, here 9 and 27 are both powers of 3. We will convert the numbers to 3 and then we will have \"3 to the power of whatever\" equals \"3 to the power of something else\". So, the 2 powers must be the same thing.\r
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\n" ); document.write( "\n" ); document.write( "\"+9%5E%282x+%2B+1%29+=+27%5Ex+\"
\n" ); document.write( "\"+%283%5E2%29%5E%282x+%2B+1%29+=+%283%5E3%29%5Ex+\"
\n" ); document.write( "\"+3%5E%282%282x%2B1%29%29+=+3%5E%283x%29+\"\r
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\n" ); document.write( "\n" ); document.write( "So now we can say that
\n" ); document.write( "\"+2%282x%2B1%29+=+3x+\"
\n" ); document.write( "\"+4x%2B2+=+3x+\"
\n" ); document.write( "\"+x%2B2+=+0+\"
\n" ); document.write( "\"+x+=+-2+\"\r
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\n" ); document.write( "\n" ); document.write( "CHECK:
\n" ); document.write( "\"+9%5E%282%28-2%29+%2B+1%29+=+27%5E%28-2%29+\"
\n" ); document.write( "\"+9%5E%28-4%2B1%29+=+27%5E%28-2%29+\"
\n" ); document.write( "\"+9%5E%28-3%29+=+27%5E%28-2%29+\"
\n" ); document.write( "\"+1%2F9%5E%283%29+=+1%2F27%5E%282%29+\"
\n" ); document.write( "\"+1%2F%283%5E2%29%5E%283%29+=+1%2F%283%5E3%29%5E%282%29+\"
\n" ); document.write( "\"+1%2F%283%5E6%29+=+1%2F%283%5E6%29+\"\r
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\n" ); document.write( "\n" ); document.write( "so we are correct.\r
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\n" ); document.write( "\n" ); document.write( "jon
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