document.write( "Question 445433: An angle is 10° more than the measure of its complement. Find the number of degrees in each angle. \n" ); document.write( "

Algebra.Com's Answer #306819 by MathLover1(20849) $\"\"$ $\"About$

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\n" ); document.write( "definition: complementary angles are a pair of angles whose measures add up to $\"90\"$ degrees\r
\n" ); document.write( "\n" ); document.write( " $\"alpha+%2B+beta=90\"$ \r
\n" ); document.write( "\n" ); document.write( "given: $\"alpha\"$ is 10° more than the measure of $\"beta\"$ \r
\n" ); document.write( "\n" ); document.write( " $\"alpha=beta+%2B10\"$ ........substitute in $\"alpha+%2B+beta=90\"$ \r
\n" ); document.write( "\n" ); document.write( " $\"beta+%2B10+%2B+beta=90\"$ ....find $\"beta\"$ \r
\n" ); document.write( "\n" ); document.write( " $\"2beta=90-10\"$ \r
\n" ); document.write( "\n" ); document.write( " $\"2beta=80\"$ \r
\n" ); document.write( "\n" ); document.write( " $\"beta=40\"$ .........now find $\"alpha\"$ \r
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( " $\"alpha=beta+%2B10\"$ \r
\n" ); document.write( "\n" ); document.write( " $\"alpha=40+%2B10\"$ \r
\n" ); document.write( "\n" ); document.write( " $\"alpha=50\"$ \r
\n" ); document.write( "\n" ); document.write( " \n" ); document.write( "

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